1 - nglc
... Choose directions as shown with the x in the direction of motion (up the ramp) and y in the direction of the normal. This greatly simplifies the math because we only have to break the force of gravity into components. The other forces all lie entirely along the x or y in the direction. We will need ...
... Choose directions as shown with the x in the direction of motion (up the ramp) and y in the direction of the normal. This greatly simplifies the math because we only have to break the force of gravity into components. The other forces all lie entirely along the x or y in the direction. We will need ...
Ch2Aug2007
... discussed further in Chapter 4. Consider solving the N-S equation for p when a and V are known. ...
... discussed further in Chapter 4. Consider solving the N-S equation for p when a and V are known. ...
Summary of the unit on force, motion, and energy
... To calculate the acceleration of the ball, we would divide the change in velocity by the (short) time it takes for the bounce—acceleration is huge! When the initial and final velocities are in different directions, the directions of the velocities have to be included in the calculations. If a movin ...
... To calculate the acceleration of the ball, we would divide the change in velocity by the (short) time it takes for the bounce—acceleration is huge! When the initial and final velocities are in different directions, the directions of the velocities have to be included in the calculations. If a movin ...
Physics 231 Topic 7: Oscillations Wade Fisher October 5-10 2012
... A h=2m tall, M=80 kg bungee jumper leaps from a H=30m bridge with a bungee cord with spring constant k = 100 N/m attached to his legs. What is the maximum length the cord needs to be if he is to avoid hitting the water below? Define A = extended “amplitude” of the bungee cord Total extension = jumpe ...
... A h=2m tall, M=80 kg bungee jumper leaps from a H=30m bridge with a bungee cord with spring constant k = 100 N/m attached to his legs. What is the maximum length the cord needs to be if he is to avoid hitting the water below? Define A = extended “amplitude” of the bungee cord Total extension = jumpe ...
Name
... 3. If a bat hits a ball with a force of 40 N, and the ball’s acceleration is 50 m/s/s, what is the mass of the ball in kg? 4. A mule pulls a plow north with a force of 200 N. The sliding friction on the plow is 100 N. What is the net force? 5. In problem #4, if the mass of the plow is 50 kg, what is ...
... 3. If a bat hits a ball with a force of 40 N, and the ball’s acceleration is 50 m/s/s, what is the mass of the ball in kg? 4. A mule pulls a plow north with a force of 200 N. The sliding friction on the plow is 100 N. What is the net force? 5. In problem #4, if the mass of the plow is 50 kg, what is ...
Newton`s Law Concept Test
... ConcepTest 5.2b Cart on Track II We just decided that the cart continues with constant velocity. What would have to be done in order to have the cart continue with constant acceleration? ...
... ConcepTest 5.2b Cart on Track II We just decided that the cart continues with constant velocity. What would have to be done in order to have the cart continue with constant acceleration? ...
PPT
... With any collision, it is imperative that you diagram the system prior to and following the collision and identify all objects involved in the collision This allows you to ensure that you calculate the total momentum for the system to properly analyze the situation ...
... With any collision, it is imperative that you diagram the system prior to and following the collision and identify all objects involved in the collision This allows you to ensure that you calculate the total momentum for the system to properly analyze the situation ...
M1 - Dynamics - Mathematics with Mr Walters
... Two particles P and Q have mass 4 kg and 0.5 kg respectively. The particles are attached to the ends of a light inextensible string. Particle P is held at rest on a fixed rough plane, which is inclined to the horizontal at an angle α where tan α = . The coefficient of friction between P and the pla ...
... Two particles P and Q have mass 4 kg and 0.5 kg respectively. The particles are attached to the ends of a light inextensible string. Particle P is held at rest on a fixed rough plane, which is inclined to the horizontal at an angle α where tan α = . The coefficient of friction between P and the pla ...
Word
... (mv ) Ft . The product Ft is called the impulse of the force. The thrust on a rocket of the jet of gases that it ejects is equal to the rate at which the jet carries away momentum. This is given by the mass ejected per second x the velocity of the jet. When two objects interact, for example in ...
... (mv ) Ft . The product Ft is called the impulse of the force. The thrust on a rocket of the jet of gases that it ejects is equal to the rate at which the jet carries away momentum. This is given by the mass ejected per second x the velocity of the jet. When two objects interact, for example in ...
Dynamics What causes motion? What causes changes in motion? Mass
... propelling it stops its action” Galileo – Newton: “ ...
... propelling it stops its action” Galileo – Newton: “ ...
Impact and Momentum - definition and units
... F dt. For motion in one dimension only, F = F i, v = vi dv and if we integrate Newton’s second law of motion, F = m , with respect to time, we obtain: dt Z ...
... F dt. For motion in one dimension only, F = F i, v = vi dv and if we integrate Newton’s second law of motion, F = m , with respect to time, we obtain: dt Z ...
