Apparent Weight - s3.amazonaws.com
... Dennis and Carmen are standing on the edge of a cliff. Dennis throws a basketball vertically upward, and at the same time Carmen throws a basketball vertically downward with the same initial speed. You are standing below the cliff observing this strange behavior. Whose ball is moving fastest when it ...
... Dennis and Carmen are standing on the edge of a cliff. Dennis throws a basketball vertically upward, and at the same time Carmen throws a basketball vertically downward with the same initial speed. You are standing below the cliff observing this strange behavior. Whose ball is moving fastest when it ...
When the net force that acts on a hockey puck is 10 N, the puck
... Interactive Question You are driving your car down a straight road at a constant velocity of 65 mph. What can you conclude about the forces acting on your car? A) The forces acting to make the car go in the forward direction must be greater than the forces acting to make the car go in the backward ...
... Interactive Question You are driving your car down a straight road at a constant velocity of 65 mph. What can you conclude about the forces acting on your car? A) The forces acting to make the car go in the forward direction must be greater than the forces acting to make the car go in the backward ...
Chapter 4 Forces and Newton’s Laws of Motion continued
... Warning: Newton’s 1st law can appear to be violated if you don’t recognize the existence of contact forces. Newton’s 1st law: for an object to remain at rest, or move with constant speed & direction, the Net Force acting on it must be ZERO. ...
... Warning: Newton’s 1st law can appear to be violated if you don’t recognize the existence of contact forces. Newton’s 1st law: for an object to remain at rest, or move with constant speed & direction, the Net Force acting on it must be ZERO. ...
Ch33
... Speed of a towed car Use the free body diagram to write Newton’s 2nd Law in component form: ΣFy = may = 0 (no change in speed up or ...
... Speed of a towed car Use the free body diagram to write Newton’s 2nd Law in component form: ΣFy = may = 0 (no change in speed up or ...
PowerPoint Lesson
... object is proportional to the force exerted on it and inversely proportional to its mass. ...
... object is proportional to the force exerted on it and inversely proportional to its mass. ...
Chapter 11 Force and Newton`s Laws Laws
... Surface Area – As surface area increases between surfaces, so does friction (more rubbing = more friction). Texture – A rougher surface = greater friction. A smoother surface = less friction. Mass/Weight – The greater the mass or weight of an object, the more friction it will create. Fluids – ...
... Surface Area – As surface area increases between surfaces, so does friction (more rubbing = more friction). Texture – A rougher surface = greater friction. A smoother surface = less friction. Mass/Weight – The greater the mass or weight of an object, the more friction it will create. Fluids – ...
Force - TeacherWeb
... • When two surfaces are in contact, the surfaces stick to each other where the dips and bumps on one surface touch the dips and bumps on the other surface. • Friction is caused by the sticking of the two surfaces at these bumps and dips. ...
... • When two surfaces are in contact, the surfaces stick to each other where the dips and bumps on one surface touch the dips and bumps on the other surface. • Friction is caused by the sticking of the two surfaces at these bumps and dips. ...
Physics Benchmark Exam #1 2008-2009
... B The scale reading will increase momentarily then will decrease as the student is moving upward from the scale. C The scale reading will increase during the entire time the student is in contact with the scale. D The scale reading will decrease momentarily then will increase as the student is movin ...
... B The scale reading will increase momentarily then will decrease as the student is moving upward from the scale. C The scale reading will increase during the entire time the student is in contact with the scale. D The scale reading will decrease momentarily then will increase as the student is movin ...
2nd 9 weeks
... I can describe the forces acting on an object undergoing horizontal rotational motion. Note: Forces acting on an object in vertical rotational motion are best analyzed using calculus, at an Honors but not Standard level. I can calculate torque given perpendicular force and lever arm. I can calculate ...
... I can describe the forces acting on an object undergoing horizontal rotational motion. Note: Forces acting on an object in vertical rotational motion are best analyzed using calculus, at an Honors but not Standard level. I can calculate torque given perpendicular force and lever arm. I can calculate ...
Unit 1 Problem Set
... 1. A bag of sugar weighs 5.00 lb on Earth. What should it weigh in newtons on the Moon, where the free-fall acceleration is 1/6 that on Earth? Repeat for Jupiter, where g is 2.64 times that on Earth. Find the mass of the bag of sugar in kilograms at each of the three locations. 2. A freight train ha ...
... 1. A bag of sugar weighs 5.00 lb on Earth. What should it weigh in newtons on the Moon, where the free-fall acceleration is 1/6 that on Earth? Repeat for Jupiter, where g is 2.64 times that on Earth. Find the mass of the bag of sugar in kilograms at each of the three locations. 2. A freight train ha ...
Work and Energy
... a) Understand the difference between constant and conserved for various systems. b) Solve problems using the formulas for impulse and momentum. Hewitt Chapter 8 16. At the National Transportation Safety test facility, they record the collision of two identical cars initially moving at 80 km/h (45 mp ...
... a) Understand the difference between constant and conserved for various systems. b) Solve problems using the formulas for impulse and momentum. Hewitt Chapter 8 16. At the National Transportation Safety test facility, they record the collision of two identical cars initially moving at 80 km/h (45 mp ...
free body diagrams: resultant force
... m/s [E] when it hits the racquet. It leaves the racquet 0.085 s later with a velocity of 40 m/s [W]. Determine the average force exerted by the racquet on the ball during this phase of its motion? (71.15 N [W]) ...
... m/s [E] when it hits the racquet. It leaves the racquet 0.085 s later with a velocity of 40 m/s [W]. Determine the average force exerted by the racquet on the ball during this phase of its motion? (71.15 N [W]) ...
Hydrostatic Forces On Submerged Surfaces
... Stability: Immersed body rotational stability of an immersed body • The rotational stability of an immersed body depends on the relative locations of the center of gravity G of the body and the center of buoyancy B, which is the centroid of the displaced volume. • An immersed body is stable if the ...
... Stability: Immersed body rotational stability of an immersed body • The rotational stability of an immersed body depends on the relative locations of the center of gravity G of the body and the center of buoyancy B, which is the centroid of the displaced volume. • An immersed body is stable if the ...
Forces 2 - Hicksville Public Schools
... 2. A 12 kg lawnmower requires 30 N of force to push it with constant velocity. What is the force of friction between the lawnmower and the lawn? 3. A 2.0 kilogram wooden object rests a on a wooden surface. What is the maximum force that you can push on the object, before it starts to move? 4. A moti ...
... 2. A 12 kg lawnmower requires 30 N of force to push it with constant velocity. What is the force of friction between the lawnmower and the lawn? 3. A 2.0 kilogram wooden object rests a on a wooden surface. What is the maximum force that you can push on the object, before it starts to move? 4. A moti ...
Chapter 6 Forces in Motion
... Projectile Motion and Gravity • Projectile motion: the curved path an object follows when thrown or propelled near the surface of the Earth. • Projectile motion has 2 components horizontal and vertical and one has no impact on the other (independent). When combined, they formed a curved path. ...
... Projectile Motion and Gravity • Projectile motion: the curved path an object follows when thrown or propelled near the surface of the Earth. • Projectile motion has 2 components horizontal and vertical and one has no impact on the other (independent). When combined, they formed a curved path. ...
Buoyancy
In science, buoyancy (pronunciation: /ˈbɔɪ.ənᵗsi/ or /ˈbuːjənᵗsi/; also known as upthrust) is an upward force exerted by a fluid that opposes the weight of an immersed object. In a column of fluid, pressure increases with depth as a result of the weight of the overlying fluid. Thus the pressure at the bottom of a column of fluid is greater than at the top of the column. Similarly, the pressure at the bottom of an object submerged in a fluid is greater than at the top of the object. This pressure difference results in a net upwards force on the object. The magnitude of that force exerted is proportional to that pressure difference, and (as explained by Archimedes' principle) is equivalent to the weight of the fluid that would otherwise occupy the volume of the object, i.e. the displaced fluid.For this reason, an object whose density is greater than that of the fluid in which it is submerged tends to sink. If the object is either less dense than the liquid or is shaped appropriately (as in a boat), the force can keep the object afloat. This can occur only in a reference frame which either has a gravitational field or is accelerating due to a force other than gravity defining a ""downward"" direction (that is, a non-inertial reference frame). In a situation of fluid statics, the net upward buoyancy force is equal to the magnitude of the weight of fluid displaced by the body.The center of buoyancy of an object is the centroid of the displaced volume of fluid.