sy30_may10_s12
... P1 atm = 1x105 N/m2 Force is normal to container surface Pressure with Depth/Height P = P0 + ρgh Gauge vs. Absolute pressure Pascal’s Principle: Same depth Same pressure Buoyancy, force, B, is always upwards B = ρfluid Vfluid displaced g (Archimedes’s Principle) Flow Continuity: Q = v2 ...
... P1 atm = 1x105 N/m2 Force is normal to container surface Pressure with Depth/Height P = P0 + ρgh Gauge vs. Absolute pressure Pascal’s Principle: Same depth Same pressure Buoyancy, force, B, is always upwards B = ρfluid Vfluid displaced g (Archimedes’s Principle) Flow Continuity: Q = v2 ...
WORK POWER MACHINES assignment
... 5. If the mass of the object were greater in trials 1, 2, 3, 4, how would that affect work done to move the object the same distances? 6. Compare trial 1 and 4. Which has the greater mechanical advantage? Explain your answer. 7. Compare trials 1, 2, 3. Is there a mechanical advantage to pulling the ...
... 5. If the mass of the object were greater in trials 1, 2, 3, 4, how would that affect work done to move the object the same distances? 6. Compare trial 1 and 4. Which has the greater mechanical advantage? Explain your answer. 7. Compare trials 1, 2, 3. Is there a mechanical advantage to pulling the ...
Forces, Newton`s Second Law
... object is moving, and see how this affects the problem. Example 4.2.2. A person of mass m is standing on the scale in the elevator. What is the scale reading if (a) the elevator is not moving, (b) the elevator is moving with constant velocity up or down (c) the elevator moves down accelerating or th ...
... object is moving, and see how this affects the problem. Example 4.2.2. A person of mass m is standing on the scale in the elevator. What is the scale reading if (a) the elevator is not moving, (b) the elevator is moving with constant velocity up or down (c) the elevator moves down accelerating or th ...
Ch 7 Kinetic Energy and Work
... gravity and then take the opposite of Wg. Example of Olympic snatch. The lift requires two separate pulls requiring different muscle groups. Instead of trying to determine how much force each pull exerted and over what distance, you can instead find the work done by gravity and then take: Wa = -Wg. ...
... gravity and then take the opposite of Wg. Example of Olympic snatch. The lift requires two separate pulls requiring different muscle groups. Instead of trying to determine how much force each pull exerted and over what distance, you can instead find the work done by gravity and then take: Wa = -Wg. ...
Chapter 3 Reading Guide
... 12. Explain what this picture shows about the relationship between mass and acceleration? If the force remains constant, then adding mass will decrease acceleration. Thus, one brick has the greatest acceleration. Three bricks has the least acceleration. ...
... 12. Explain what this picture shows about the relationship between mass and acceleration? If the force remains constant, then adding mass will decrease acceleration. Thus, one brick has the greatest acceleration. Three bricks has the least acceleration. ...
Friction
... between objects that are sliding with respect to one another. • Once enough force has been applied to the object to overcome static friction and get the object to move, the friction changes to sliding (or kinetic) friction. • Sliding (kinetic) friction is less than static friction. • If the componen ...
... between objects that are sliding with respect to one another. • Once enough force has been applied to the object to overcome static friction and get the object to move, the friction changes to sliding (or kinetic) friction. • Sliding (kinetic) friction is less than static friction. • If the componen ...
Overheads - Physics 420 UBC Physics Demonstrations
... • The friction between the road and a car’s wheels is called traction. • Traction allows cars to accelerate and to change direction. • What happens when the surface the wheels contact changes (the coefficient of friction is ...
... • The friction between the road and a car’s wheels is called traction. • Traction allows cars to accelerate and to change direction. • What happens when the surface the wheels contact changes (the coefficient of friction is ...
Lake Compounce General Info
... centrifugal force A reaction force to centripetal force, which you feel in a moving frame. This is a fictitious force. When your body responds to an acceleration you think there is a force pushing you back. centripetal force A force acting toward the center which makes objects turn. circumference Th ...
... centrifugal force A reaction force to centripetal force, which you feel in a moving frame. This is a fictitious force. When your body responds to an acceleration you think there is a force pushing you back. centripetal force A force acting toward the center which makes objects turn. circumference Th ...
AS90183_NBC_1a
... in which the speed value is calculated. For example if we measure the distance in kilometres (km) and time in hours (h) then speed will be defined in km per hour. Often in physics and science since we measure in metres and seconds, speed is quoted in metres per ...
... in which the speed value is calculated. For example if we measure the distance in kilometres (km) and time in hours (h) then speed will be defined in km per hour. Often in physics and science since we measure in metres and seconds, speed is quoted in metres per ...
ALL Newtons Second Law
... a) What is the net force parallel to the plane? b) What is the acceleration parallel to the plane? 22. A sled is being pulled towards the left on a flat, horizontal surface by a rope that makes a 30 degree angle with the horizontal. The mass of the sled is 40 kg, the tension in the rope is 200 N and ...
... a) What is the net force parallel to the plane? b) What is the acceleration parallel to the plane? 22. A sled is being pulled towards the left on a flat, horizontal surface by a rope that makes a 30 degree angle with the horizontal. The mass of the sled is 40 kg, the tension in the rope is 200 N and ...
Chapter 4 - faculty at Chemeketa
... Coin and feather fall with air present • Feather reaches terminal velocity very quickly and falls slowly at constant speed, reaching the bottom after the coin does. • Coin falls very quickly and air resistance doesn’t build up to its weight over short-falling distances, which is why the coin hits th ...
... Coin and feather fall with air present • Feather reaches terminal velocity very quickly and falls slowly at constant speed, reaching the bottom after the coin does. • Coin falls very quickly and air resistance doesn’t build up to its weight over short-falling distances, which is why the coin hits th ...
Newton`s First Law
... in the same direction as the net force, and inversely proportional to the mass of the object. This verbal statement can be expressed in equation form as follows: a = Fnet / m The above equation is often rearranged to a more familiar form as shown below. The net force is equated to the product of the ...
... in the same direction as the net force, and inversely proportional to the mass of the object. This verbal statement can be expressed in equation form as follows: a = Fnet / m The above equation is often rearranged to a more familiar form as shown below. The net force is equated to the product of the ...
Ch2Fall2012
... Condition for static equilibrium: (1) ∑Fv=0 and (2) ∑M=0 Condition (2) is met only when C and G coincide, otherwise we can have either a righting moment (stable) or a heeling moment (unstable) when the body is heeled. ...
... Condition for static equilibrium: (1) ∑Fv=0 and (2) ∑M=0 Condition (2) is met only when C and G coincide, otherwise we can have either a righting moment (stable) or a heeling moment (unstable) when the body is heeled. ...
Circular Motion Review A student spinning a 0.10
... ball at the end of a 0.50-meter string in a horizontal circle at a constant speed of 10. meters per second. If the magnitude of the force applied to the string by the student's hand is increased, the magnitude of the acceleration of the ball in its circular path will A. decrease B. increase C. remai ...
... ball at the end of a 0.50-meter string in a horizontal circle at a constant speed of 10. meters per second. If the magnitude of the force applied to the string by the student's hand is increased, the magnitude of the acceleration of the ball in its circular path will A. decrease B. increase C. remai ...
Circular Motion Review
... ball at the end of a 0.50-meter string in a horizontal circle at a constant speed of 10. meters per second. If the magnitude of the force applied to the string by the student's hand is increased, the magnitude of the acceleration of the ball in its circular path will A. decrease B. increase C. remai ...
... ball at the end of a 0.50-meter string in a horizontal circle at a constant speed of 10. meters per second. If the magnitude of the force applied to the string by the student's hand is increased, the magnitude of the acceleration of the ball in its circular path will A. decrease B. increase C. remai ...
Free-body Diagrams
... The force of gravity is an example of a force that exists between objects without them having to be in contact. The force of gravity exerted by one object (like the Earth) on another object, like an apple, is proportional to the mass of the apple. The direction of the force is toward the object appl ...
... The force of gravity is an example of a force that exists between objects without them having to be in contact. The force of gravity exerted by one object (like the Earth) on another object, like an apple, is proportional to the mass of the apple. The direction of the force is toward the object appl ...
Gravity is a force exerted by masses.
... short time. If you were standing on a scale during the downward acceleration, the scale would show that you weighed less than usual. Your mass would not have changed, nor would the pull of gravity. What would cause the apparent weight loss? When the elevator is still, the entire force of your weight ...
... short time. If you were standing on a scale during the downward acceleration, the scale would show that you weighed less than usual. Your mass would not have changed, nor would the pull of gravity. What would cause the apparent weight loss? When the elevator is still, the entire force of your weight ...
L16-Pressure-and-Winds
... – The atmospheric molecules are held near surface by gravity – Pressure itself reflects the weight of the mass of overlying atmosphere – Defined as force per unit area at the surface – Units of Pascal (1 N/m2) – In the atmosphere, we measure pressure in millibars (mb) – It is important to remember t ...
... – The atmospheric molecules are held near surface by gravity – Pressure itself reflects the weight of the mass of overlying atmosphere – Defined as force per unit area at the surface – Units of Pascal (1 N/m2) – In the atmosphere, we measure pressure in millibars (mb) – It is important to remember t ...
Buoyancy
In science, buoyancy (pronunciation: /ˈbɔɪ.ənᵗsi/ or /ˈbuːjənᵗsi/; also known as upthrust) is an upward force exerted by a fluid that opposes the weight of an immersed object. In a column of fluid, pressure increases with depth as a result of the weight of the overlying fluid. Thus the pressure at the bottom of a column of fluid is greater than at the top of the column. Similarly, the pressure at the bottom of an object submerged in a fluid is greater than at the top of the object. This pressure difference results in a net upwards force on the object. The magnitude of that force exerted is proportional to that pressure difference, and (as explained by Archimedes' principle) is equivalent to the weight of the fluid that would otherwise occupy the volume of the object, i.e. the displaced fluid.For this reason, an object whose density is greater than that of the fluid in which it is submerged tends to sink. If the object is either less dense than the liquid or is shaped appropriately (as in a boat), the force can keep the object afloat. This can occur only in a reference frame which either has a gravitational field or is accelerating due to a force other than gravity defining a ""downward"" direction (that is, a non-inertial reference frame). In a situation of fluid statics, the net upward buoyancy force is equal to the magnitude of the weight of fluid displaced by the body.The center of buoyancy of an object is the centroid of the displaced volume of fluid.