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Unit 2: Vector Dynamics
Unit 2: Vector Dynamics

Conversions: 15ft × 12 in 1 ft × 2.54 cm 1 in × 1 m 100 cm = 4.57 m
Conversions: 15ft × 12 in 1 ft × 2.54 cm 1 in × 1 m 100 cm = 4.57 m

physics - Bharatiya Vidya Bhavans School
physics - Bharatiya Vidya Bhavans School

Physics and the Fair: Forces and Motion
Physics and the Fair: Forces and Motion

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... Question 3 A circular, horizontal pipe uniformly tapers from a diameter of 160 mm to a diameter of 70 mm. Hydraulic oil, of density 1200 kgm-3, flows through the pipe from the greater diameter cross-section to the smaller diameter cross-section. The pressure at the greater diameter cross-section is ...
Conservation of Momentum in One Dimension
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astronomy history time machine

1. Find the weight of a 2.3 kg bowling ball on Earth.
1. Find the weight of a 2.3 kg bowling ball on Earth.

The correct answers are written in bold, italic and underlined. The
The correct answers are written in bold, italic and underlined. The

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reading – motion and forces review – innovation lab

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Study Guide For Final File

... second in three seconds. Calculate the acceleration of the sailboat. (p.34) 9) A car accelerates from 0 to 20 meters per second in 10 seconds. Calculate the acceleration. (p.34) 10) Please state Newton’s Second Law: ...
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1 - ActiveClassroom!

... 36. The driver of a 2000 kg car moving at 30 m/s presses on the break pedal. If the braking force is 10,000 N, how far does the car travel before stopping? a. 45 m b. 90 m c. 135 m d. 180 m 37. A 2 kg ball moving at 3 m/s hits a wall and bounces off. Immediately after the collision, it moves at 3 m ...
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Jeopardy

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... What happened to the lines? There are traffic lights at this intersection, and each day hundreds of cars stop just to the left of the fines. When the light turns green, the cars accelerate to the right (Fig. 2). To achieve this acceleration, the car tires exert a backward force on the road (to the ...
Newton`s Laws webquest
Newton`s Laws webquest

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CP Physics – Midterm Review

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Chapter 3: The Basics of Classical Mechanics
Chapter 3: The Basics of Classical Mechanics

... of classical mechanics to this problem would be to divide it into two parts. The first of these would be to write the equations of motion for an object moving under the influence of an arbitrary collection of mass points. The second part then consists of solving those equations. Therefore it is appr ...
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Ch 11 Rolling, Torque and Angular Momentum
Ch 11 Rolling, Torque and Angular Momentum

... Forces of rolling If a wheel rolls smoothly, there is no sliding at the contact point so there is no friction. However, if there is an external force that produces an acceleration, there will be an angular acceleration, . The acceleration will make the wheel want to slide at the contact point. Then ...
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Standards SP1. Students will analyze the relationships between

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Circular Motion RS

... 1. When a car goes around a curve, what force keeps the car on the road? 2. What is the direction of the centripetal acceleration of an object in uniform circular motion? Why? 3. A ball is whirled around in a circle. What happens to the centripetal acceleration if the velocity is doubled? 4. If a st ...
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Newton's laws of motion

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