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Lesson 1

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Lesson 7 part 2 Solutions

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... Note that (x + 3)2 is either positive or zero. Therefore, the only solution of the inequality (x + 2)(x + 4) ≤ −1 is x = −3. In a similar way one can show that the solution of the inequality (x + 2)(x + 4) ≥ −1 is all real numbers. ...
The circle had a relatively easy locus definition, ie the
The circle had a relatively easy locus definition, ie the

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Elementary algebra

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