
prime numbers and encryption
... Proof: (Based on [3]) First we'll show that any integer can be factored. Start with sorne integer n > l. If 11 is prime, we are done. Otherwise 11 = ab where a, b > l. If a and b are prime, we are done. If one or both are not prime apply the same argument to each piece. For example, if a is prime bu ...
... Proof: (Based on [3]) First we'll show that any integer can be factored. Start with sorne integer n > l. If 11 is prime, we are done. Otherwise 11 = ab where a, b > l. If a and b are prime, we are done. If one or both are not prime apply the same argument to each piece. For example, if a is prime bu ...
DMT irm 3 - Information Age Publishing
... 20. (a) a | a because a = a · 1. Thus | is reflexive. (b) In Exercise 10 we proved that if a | b and b | c, then a | c. This is the statement of the transitive property for “divides.” (c) 6 divides 12 but 12 does not divide 6. (d) Since a | b there is an integer k with a = bk. Since b | a there is a ...
... 20. (a) a | a because a = a · 1. Thus | is reflexive. (b) In Exercise 10 we proved that if a | b and b | c, then a | c. This is the statement of the transitive property for “divides.” (c) 6 divides 12 but 12 does not divide 6. (d) Since a | b there is an integer k with a = bk. Since b | a there is a ...