CC-80 art 6
... 4. Concrete and mortars Concrete is a mixture of cement clinker, water, gypsum (CaSO4.2H2O), and aggregates such as quartz, limestone, dolomite, and slag. Clinker is produced by the reaction of calcium oxide (CaO=C), silica (SiO2=S), alumina (Al2O3=A) and ferric oxide (Fe2O3=F) at about 1500ºC to gi ...
... 4. Concrete and mortars Concrete is a mixture of cement clinker, water, gypsum (CaSO4.2H2O), and aggregates such as quartz, limestone, dolomite, and slag. Clinker is produced by the reaction of calcium oxide (CaO=C), silica (SiO2=S), alumina (Al2O3=A) and ferric oxide (Fe2O3=F) at about 1500ºC to gi ...
AP Chem -‐ Unit 1 Part 1 AP Chemistry 2016
... A rectangular solid measures 1.0 m by 5.6 cm by 2.1dm. Express its volume in cubic meters, liters, cubic inches and cubic feet. The density of pure silver is 10.5 g/cm3 at 20ºC. If 5.25 ...
... A rectangular solid measures 1.0 m by 5.6 cm by 2.1dm. Express its volume in cubic meters, liters, cubic inches and cubic feet. The density of pure silver is 10.5 g/cm3 at 20ºC. If 5.25 ...
S - Valdosta State University
... S solid is (larger/smaller) than S liquid is (larger/smaller) than S gas • Then, all substances have ________ (positive/negative) entropy values at T > 0K. ...
... S solid is (larger/smaller) than S liquid is (larger/smaller) than S gas • Then, all substances have ________ (positive/negative) entropy values at T > 0K. ...
ch22_lecture_6e_final
... liquid oils to form C-C bonds in solid fats and margarine. – Partially hydrogenated vegetable fats and oils are present in a wide variety of foods. ...
... liquid oils to form C-C bonds in solid fats and margarine. – Partially hydrogenated vegetable fats and oils are present in a wide variety of foods. ...
H reactants
... 1. Definition – energy that is in the process of flowing from a warmer object to a cooler object. 2. Symbol – q 3. Measuring heat a. calorie – amount of heat required to raise the temperature of 1 gram of pure water by 1 degree Celsius ...
... 1. Definition – energy that is in the process of flowing from a warmer object to a cooler object. 2. Symbol – q 3. Measuring heat a. calorie – amount of heat required to raise the temperature of 1 gram of pure water by 1 degree Celsius ...
Balancing Chemical Equations Academic Success Center Science Tutoring Area *
... If polyatomic ions are the same on the reactant side as the product side, balance the polyatomic ion as one group or one ion ●2(NH4)3PO4(aq) + 3 CaCl2 Ca3(PO4)2(s) + 6 NH4Cl(aq) 24 hydrogens, 6 ...
... If polyatomic ions are the same on the reactant side as the product side, balance the polyatomic ion as one group or one ion ●2(NH4)3PO4(aq) + 3 CaCl2 Ca3(PO4)2(s) + 6 NH4Cl(aq) 24 hydrogens, 6 ...
get Assignment File
... surroundings. We can answer this argument two ways (They both yield the same result.): 1) We can define the system as consisting only of the ions that have reacted and the small amount of water that they generated in the reaction. Then the surroundings include the solvent water, and essentially all ...
... surroundings. We can answer this argument two ways (They both yield the same result.): 1) We can define the system as consisting only of the ions that have reacted and the small amount of water that they generated in the reaction. Then the surroundings include the solvent water, and essentially all ...
AP Chemistry Summer Assignment
... you can find any chemistry information or help you might need. If you do not like the videos that I suggest, please feel free to watch any others that you find interesting. AP Chemistry will teach you to think at higher levels. You will be forced to think and apply concepts to new situations or even ...
... you can find any chemistry information or help you might need. If you do not like the videos that I suggest, please feel free to watch any others that you find interesting. AP Chemistry will teach you to think at higher levels. You will be forced to think and apply concepts to new situations or even ...
Cleaning Up With Atom Economy
... Atom economy means maximizing the incorporation of material from the starting materials or reagents into the final product. It is essentially pollution prevention at the molecular level. For example, a chemist practicing atom economy would choose to synthesize a needed product by putting together ba ...
... Atom economy means maximizing the incorporation of material from the starting materials or reagents into the final product. It is essentially pollution prevention at the molecular level. For example, a chemist practicing atom economy would choose to synthesize a needed product by putting together ba ...
MISE - Physical Basis of Chemistry
... Chemical formula. The actual amounts of each element would change the ratio and thus the formula. 3. Deducing the mole … the chemist’s “dozen”… Up to now, we’ve been talking about relative atomic weights and we have been working in ratio - using the “triangle”. Since individual weights appear in the ...
... Chemical formula. The actual amounts of each element would change the ratio and thus the formula. 3. Deducing the mole … the chemist’s “dozen”… Up to now, we’ve been talking about relative atomic weights and we have been working in ratio - using the “triangle”. Since individual weights appear in the ...
Chapter 2 power point File
... An element is so small that you need a small unit just to measure them Atomic mass unit (amu) is 1.66 x 10-24 g The atom carbon has a weight of 12 amu Hydrogen has a weight of 1 amu The large number in each square of the periodic table is an element’s average weight in amu The atomic mass has two im ...
... An element is so small that you need a small unit just to measure them Atomic mass unit (amu) is 1.66 x 10-24 g The atom carbon has a weight of 12 amu Hydrogen has a weight of 1 amu The large number in each square of the periodic table is an element’s average weight in amu The atomic mass has two im ...
AP Chemistry Second Semester Notes
... the measurement with the fewest 2. average atomic mass (periodic table mass) 3. +, –: answer has same end decimal position a. isotopes have fixed % in natural sample as measurement with left most end position b. 100mav = %1m1 + %2m2 + ... 2. SI measuring system 3. forms of matter a. summary chart a. ...
... the measurement with the fewest 2. average atomic mass (periodic table mass) 3. +, –: answer has same end decimal position a. isotopes have fixed % in natural sample as measurement with left most end position b. 100mav = %1m1 + %2m2 + ... 2. SI measuring system 3. forms of matter a. summary chart a. ...
Chapter6 - GEOCITIES.ws
... Conversions of different forms of energy are governed by : The Law of Conservation of Energy: Energy may be converted from one form to another, but the total quantity of energy remains constant. ...
... Conversions of different forms of energy are governed by : The Law of Conservation of Energy: Energy may be converted from one form to another, but the total quantity of energy remains constant. ...
aq - HCC Learning Web
... • Aqueous solutions of lead(II) nitrate and potassium iodide produce a yellow precipitate of lead(II) iodide and an aqueous solution of potassium nitrate Pb(NO3)2(aq) + KI(aq) PbI2(s) + KNO3(aq) • Aqueous solutions of calcium nitrate and sodium carbonate react to give a white precipitate of calciu ...
... • Aqueous solutions of lead(II) nitrate and potassium iodide produce a yellow precipitate of lead(II) iodide and an aqueous solution of potassium nitrate Pb(NO3)2(aq) + KI(aq) PbI2(s) + KNO3(aq) • Aqueous solutions of calcium nitrate and sodium carbonate react to give a white precipitate of calciu ...
AP `94 Multiple Choice
... 16. Commercial vinegar was titrated with NaOH solution to determine the content of acetic acid, 20. … Ag+ + … AsH3(g) + … OH– … Ag(s) HC2H3O2. For 20.0 milliliters of the vinegar, 26.7 + … H3AsO3(aq) + … H2O milliliters of 0.600–molar NaOH solution was When the equation above is balanced with lowe ...
... 16. Commercial vinegar was titrated with NaOH solution to determine the content of acetic acid, 20. … Ag+ + … AsH3(g) + … OH– … Ag(s) HC2H3O2. For 20.0 milliliters of the vinegar, 26.7 + … H3AsO3(aq) + … H2O milliliters of 0.600–molar NaOH solution was When the equation above is balanced with lowe ...
Sign of enthalpy changes Exothermic vs endothermic Acid
... If n = 0.3 mol, Hm = H/n = –2.4 x 10–3 cal / (0.3 x 10–6 mol) = –8 kcal/mol If n = 0.2 mol, Hm = H/n = –2.4 x 10–3 cal / (0.2 x 10–6 mol) = –12 kcal/mol If n = 0.1 mol, Hm = H/n = –2.4 x 10–3 cal / (0.1 x 10–6 mol) = –24 kcal/mol ...
... If n = 0.3 mol, Hm = H/n = –2.4 x 10–3 cal / (0.3 x 10–6 mol) = –8 kcal/mol If n = 0.2 mol, Hm = H/n = –2.4 x 10–3 cal / (0.2 x 10–6 mol) = –12 kcal/mol If n = 0.1 mol, Hm = H/n = –2.4 x 10–3 cal / (0.1 x 10–6 mol) = –24 kcal/mol ...
unit 8 – compound stoichiometry
... NOTE: formulas are typically written from least electronegative to most electronegative. METALS FIRST! STEPS to solve empirical formula problems: 1. % to mass – the easiest way to convert % to mass is to assume 100 grams. (42% of 100 g = 42 g!) 2. mass to mole – USE MOLAR MASS! Be sure to leave your ...
... NOTE: formulas are typically written from least electronegative to most electronegative. METALS FIRST! STEPS to solve empirical formula problems: 1. % to mass – the easiest way to convert % to mass is to assume 100 grams. (42% of 100 g = 42 g!) 2. mass to mole – USE MOLAR MASS! Be sure to leave your ...
2H 2 O(g)
... The number of steps does not matter ΔH for any process can be measured as long as we know the ΔH for each of the individual steps This allows us to find ΔH for reactions that are difficult to measure. ...
... The number of steps does not matter ΔH for any process can be measured as long as we know the ΔH for each of the individual steps This allows us to find ΔH for reactions that are difficult to measure. ...
2010 Exam
... Select the letter of the correct response from those provided. EITHER shade the letter on your computer scorable card OR place the letter in the blank provided on your Multiple Choice Answer Sheet, whichever format is being used by your school for this exam. Do ALL questions in this section. ...
... Select the letter of the correct response from those provided. EITHER shade the letter on your computer scorable card OR place the letter in the blank provided on your Multiple Choice Answer Sheet, whichever format is being used by your school for this exam. Do ALL questions in this section. ...
Chemistry Academic v. 2016
... Describe the evolution of atomic theory of the atom and how it contributed to the modern model of the atom. Differentiate between the mass number of an isotope and an average atomic mass of an element and distinguish among the isotopic forms of elements. Recognize discoveries from Daltons atomic the ...
... Describe the evolution of atomic theory of the atom and how it contributed to the modern model of the atom. Differentiate between the mass number of an isotope and an average atomic mass of an element and distinguish among the isotopic forms of elements. Recognize discoveries from Daltons atomic the ...
I have put this in the format of the 1984 exam
... absolute temperature is doubled, which of the following is also doubled? (A) The density of the gas (B) The pressure of the gas (C) The average velocity of the gas molecules (D) The number of molecules per cm3 (E) The potential energy of the molecules 22. 1s2 2s22p6 3s23p3 Atoms of an element, X, ha ...
... absolute temperature is doubled, which of the following is also doubled? (A) The density of the gas (B) The pressure of the gas (C) The average velocity of the gas molecules (D) The number of molecules per cm3 (E) The potential energy of the molecules 22. 1s2 2s22p6 3s23p3 Atoms of an element, X, ha ...
MODULE FOR INTERNATIONAL STANDARD CLASS
... alkanes and cycloalkanes. The object of petroleum refining is to obtain various hydrocarbon products from the mixture. In part, this is accomplished by fractional distillation of the petroleum, but the demand for certain products, particularly gasoline, is greater than what can be supplied by distil ...
... alkanes and cycloalkanes. The object of petroleum refining is to obtain various hydrocarbon products from the mixture. In part, this is accomplished by fractional distillation of the petroleum, but the demand for certain products, particularly gasoline, is greater than what can be supplied by distil ...
Stoichiometry
Stoichiometry /ˌstɔɪkiˈɒmɨtri/ is the calculation of relative quantities of reactants and products in chemical reactions.Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of product can be empirically determined, then the amount of the other reactants can also be calculated.As seen in the image to the right, where the balanced equation is:CH4 + 2 O2 → CO2 + 2 H2O.Here, one molecule of methane reacts with two molecules of oxygen gas to yield one molecule of carbon dioxide and two molecules of water. Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry. In the example above, reaction stoichiometry measures the relationship between the methane and oxygen as they react to form carbon dioxide and water.Because of the well known relationship of moles to atomic weights, the ratios that are arrived at by stoichiometry can be used to determine quantities by weight in a reaction described by a balanced equation. This is called composition stoichiometry.Gas stoichiometry deals with reactions involving gases, where the gases are at a known temperature, pressure, and volume and can be assumed to be ideal gases. For gases, the volume ratio is ideally the same by the ideal gas law, but the mass ratio of a single reaction has to be calculated from the molecular masses of the reactants and products. In practice, due to the existence of isotopes, molar masses are used instead when calculating the mass ratio.