Slides for Session #19
... – Build the t statistic (m-v)/SE – Reject the H0 with significance level 1% if the t statistic is outside the range [-t0.005 , t0.005] – Reject the H0 with significance level 5% if the t statistic is outside the range [-t0.025 , t0.025] – Reject the H0 with significance level 10% if the t statistic ...
... – Build the t statistic (m-v)/SE – Reject the H0 with significance level 1% if the t statistic is outside the range [-t0.005 , t0.005] – Reject the H0 with significance level 5% if the t statistic is outside the range [-t0.025 , t0.025] – Reject the H0 with significance level 10% if the t statistic ...
Practice Test 3 answers
... waiting time of 12 minutes and a standard deviation of3.4 minutes. Use the critical value approach to test at the 2.5% significance level if the mean waiting time for all customers who visit this bank is greater than 1b minutes. Assume that the waiting time for all customers is normally distributed ...
... waiting time of 12 minutes and a standard deviation of3.4 minutes. Use the critical value approach to test at the 2.5% significance level if the mean waiting time for all customers who visit this bank is greater than 1b minutes. Assume that the waiting time for all customers is normally distributed ...
On a separate piece of paper, answer the following questions
... If a subject is randomly selected and tested, find the probability that his score will be between 75 and 100. If a subject is randomly selected and tested, find the probability that his score will be below 85. If a subject is randomly selected and tested, find the probability that his score will be ...
... If a subject is randomly selected and tested, find the probability that his score will be between 75 and 100. If a subject is randomly selected and tested, find the probability that his score will be below 85. If a subject is randomly selected and tested, find the probability that his score will be ...
Tests on the population mean (known variance)
... |z| > zα/2 . The problem asks for a test at level 5%, so α = .05 and zα/2 = 1.96 ≈ 2. We will reject H0 if |z| > zα/2 , i.e. |z| > 2. ...
... |z| > zα/2 . The problem asks for a test at level 5%, so α = .05 and zα/2 = 1.96 ≈ 2. We will reject H0 if |z| > zα/2 , i.e. |z| > 2. ...
