![Measures of Central Tendency](http://s1.studyres.com/store/data/008531608_1-fe25eae1bc2eb094abc0b751ea9467e8-300x300.png)
AP Statistics - edventure-GA
... scored 45. Scores on the ABC exam are approximately normally distributed with a mean of 40 and a standard deviation of 10. The second student took the XYZ exam and scored 88. Scores on the XYZ exam are approximately normally distributed with a mean of 80 and a standard deviation of 16. Which student ...
... scored 45. Scores on the ABC exam are approximately normally distributed with a mean of 40 and a standard deviation of 10. The second student took the XYZ exam and scored 88. Scores on the XYZ exam are approximately normally distributed with a mean of 80 and a standard deviation of 16. Which student ...
University of Toronto Scarborough STAB22 Final Examination
... 24. In the situation described in Question 22, it is desired to make the answer obtained using the normal approximation closer to the exact answer. Which of the following would make the normal approximation more accurate? (a) allowing in some way for the fact that the number of sampled males has to ...
... 24. In the situation described in Question 22, it is desired to make the answer obtained using the normal approximation closer to the exact answer. Which of the following would make the normal approximation more accurate? (a) allowing in some way for the fact that the number of sampled males has to ...
Solutions - DePaul QRC
... b. Between which two values do the middle 95% of adult golden trout weights lie? Looking 95% in the area column in the table, we z 2. So the middle 95% will lie between 3 – 2*1.3 = 0.4 and 3 + 2*1.3 = 5.6 lbs. Using a TI calculator, we find InvNorm(0.025,3,1.3) 0.45 lbs and InvNorm(0.975,3,1.3) ...
... b. Between which two values do the middle 95% of adult golden trout weights lie? Looking 95% in the area column in the table, we z 2. So the middle 95% will lie between 3 – 2*1.3 = 0.4 and 3 + 2*1.3 = 5.6 lbs. Using a TI calculator, we find InvNorm(0.025,3,1.3) 0.45 lbs and InvNorm(0.975,3,1.3) ...
Standard Deviation
... For data that has a normal distribution, 68% of the data lies within one standard deviation of the mean. ...
... For data that has a normal distribution, 68% of the data lies within one standard deviation of the mean. ...