CHAPTER 3
... chlorine atom ? (5.89 X 10-23 g) 2. What is the avg. mass in grams of one ethanol (C2H5OH) molecule ? (7.65 X 10-23 g) 3. How many moles of PbCrO4 (Lead Chromate) are in 45.6 grams ? (0.141 mol) 4. How many HCl (hydrogen chloride) molecules are in 46.0 grams ? (7.60 X 1023 molecules) ...
... chlorine atom ? (5.89 X 10-23 g) 2. What is the avg. mass in grams of one ethanol (C2H5OH) molecule ? (7.65 X 10-23 g) 3. How many moles of PbCrO4 (Lead Chromate) are in 45.6 grams ? (0.141 mol) 4. How many HCl (hydrogen chloride) molecules are in 46.0 grams ? (7.60 X 1023 molecules) ...
Calculations with Chemical Reactions
... Molecular mass– the mass of one molecule. Molecular mass is equal to the total mass of all the elements making up a molecule. Mole –a unit of measurement widely used in chemistry to measure an amount of a particular substance. One mole has approximately 6.022 x 1023 elementary entities (atoms, molec ...
... Molecular mass– the mass of one molecule. Molecular mass is equal to the total mass of all the elements making up a molecule. Mole –a unit of measurement widely used in chemistry to measure an amount of a particular substance. One mole has approximately 6.022 x 1023 elementary entities (atoms, molec ...
mass-mass problems.
... reaction (substance A) and asked to calculate the mass of a different substance in the reaction (substance B). This will be a 3-step dimensional analysis conversion. 1. Convert grams of A to moles of A using the molar mass of A. 2. Convert moles of A to moles of B using the coefficients from the bal ...
... reaction (substance A) and asked to calculate the mass of a different substance in the reaction (substance B). This will be a 3-step dimensional analysis conversion. 1. Convert grams of A to moles of A using the molar mass of A. 2. Convert moles of A to moles of B using the coefficients from the bal ...
Unit 2 Powerpoint Notes
... product that can be produced from a given amount of reactant (found with stoichiometry). • The actual yield of a product is the measured amount of that product obtained from a reaction (given in problem). • The percentage yield is the ratio of the actual yield to the theoretical yield, multiplied by ...
... product that can be produced from a given amount of reactant (found with stoichiometry). • The actual yield of a product is the measured amount of that product obtained from a reaction (given in problem). • The percentage yield is the ratio of the actual yield to the theoretical yield, multiplied by ...
Chemical Quantities: Stoichiometry and the Mole
... 12) When a barium chloride solution is mixed with a solution containing excess aluminum sulfate, 0.888 g of barium sulfate is obtained. What mass of barium sulfate was contained in the solution? 13) A 0.187 g sample of impure aluminum metaal was treated with excess sulfuric acid. 0.921 g of aluminu ...
... 12) When a barium chloride solution is mixed with a solution containing excess aluminum sulfate, 0.888 g of barium sulfate is obtained. What mass of barium sulfate was contained in the solution? 13) A 0.187 g sample of impure aluminum metaal was treated with excess sulfuric acid. 0.921 g of aluminu ...
chemistry notes on the mole - lessons
... When you read the ingredient list on the back of a package of food, have you ever noticed how much of each ingredient is contained in a serving? We can compare the quantity of sugar, fat, or vitamins and minerals between different brands as well. The quantitative information helps us decide which pr ...
... When you read the ingredient list on the back of a package of food, have you ever noticed how much of each ingredient is contained in a serving? We can compare the quantity of sugar, fat, or vitamins and minerals between different brands as well. The quantitative information helps us decide which pr ...
some basic concepts of chemistry
... chemistry laboratories, smaller volumes are used. Hence, volume is often denoted in cm3 or dm3 units. ...
... chemistry laboratories, smaller volumes are used. Hence, volume is often denoted in cm3 or dm3 units. ...
258-261
... n the last section we saw how to use the balanced equation for a reaction to calculate the numbers of moles of reactants and products for a particular case. However, moles represent numbers of molecules, and we cannot count molecules directly. In chemistry we count by weighing. Therefore, in this se ...
... n the last section we saw how to use the balanced equation for a reaction to calculate the numbers of moles of reactants and products for a particular case. However, moles represent numbers of molecules, and we cannot count molecules directly. In chemistry we count by weighing. Therefore, in this se ...
Solution - gearju.com
... The conversion factor on the left is the one we need because it has number of S atoms in the numerator. We can solve the problem by first calculating the number of moles contained in 16.3 g of S, and then calculating the number of S atoms from the number of moles of S: ...
... The conversion factor on the left is the one we need because it has number of S atoms in the numerator. We can solve the problem by first calculating the number of moles contained in 16.3 g of S, and then calculating the number of S atoms from the number of moles of S: ...
Chapter 11 – The Mole
... Step 6 – Divide the molar given in the problem by the empirical molar mass calculated in step 5. This answer will provide you with the number needed to multiply the empirical formula by to get the molecular formula. ...
... Step 6 – Divide the molar given in the problem by the empirical molar mass calculated in step 5. This answer will provide you with the number needed to multiply the empirical formula by to get the molecular formula. ...
Math Review
... This chapter uses conversion factors frequently to solve problems. Conversion factors are ratios written in the fraction form (a/b). Some of the conversion factors you will see in this chapter include metric-to-metric conversion factors such as: 1 gram of silver is 1000 mg of silver 1 liter of water ...
... This chapter uses conversion factors frequently to solve problems. Conversion factors are ratios written in the fraction form (a/b). Some of the conversion factors you will see in this chapter include metric-to-metric conversion factors such as: 1 gram of silver is 1000 mg of silver 1 liter of water ...
Chemistry 211 - George Mason University
... The Study of Chemistry • Chemistry = the study of the composition, properties and transformations of matter. • Matter = physical material of the universe. • Elements = basic building blocks of all other forms of matter. • Atoms = small particles derived from one the elements. All matter can be desc ...
... The Study of Chemistry • Chemistry = the study of the composition, properties and transformations of matter. • Matter = physical material of the universe. • Elements = basic building blocks of all other forms of matter. • Atoms = small particles derived from one the elements. All matter can be desc ...
Stoichiometry
... 2K + 2H20 2KOH + H2 1. Identify the known… K 2. Identify the unknown…H2 3. To solve this problem, you need to know how the unknown moles of H2 are related to the know moles of K 4. The correct ratio should have the moles of unknown in the numerator and the moles of the known should be in the denom ...
... 2K + 2H20 2KOH + H2 1. Identify the known… K 2. Identify the unknown…H2 3. To solve this problem, you need to know how the unknown moles of H2 are related to the know moles of K 4. The correct ratio should have the moles of unknown in the numerator and the moles of the known should be in the denom ...
17074_scale-1
... A line which is divided into suitable no. of equal parts or units, the first part of which is further sub-divided into small parts or sub-units of main unit is known as Plain Scale. The Plain scales are used to represent either two units (such as Kilometers, Decimeters ) OR one unit and its fraction ...
... A line which is divided into suitable no. of equal parts or units, the first part of which is further sub-divided into small parts or sub-units of main unit is known as Plain Scale. The Plain scales are used to represent either two units (such as Kilometers, Decimeters ) OR one unit and its fraction ...
Mass Relationships in Chemical Reactions
... Solution If we have 100 g of ascorbic acid, then each percentage can be converted directly to grams. In this sample, there will be 40.92 g of C, 4.58 g of H, and 54.50 g of O. Because the subscripts in the formula represent a mole ratio, we need to convert the grams of each element to moles. The con ...
... Solution If we have 100 g of ascorbic acid, then each percentage can be converted directly to grams. In this sample, there will be 40.92 g of C, 4.58 g of H, and 54.50 g of O. Because the subscripts in the formula represent a mole ratio, we need to convert the grams of each element to moles. The con ...
Can atoms be counted or measured
... 4. The atomic _______________ will give you this value for each element (number below the symbol) 5. For example, the atomic mass of Copper is 63.55 amu. This means that 1 mole of Copper will weigh 63.55 grams. 6. Don’t forget that mass is related to the number of amu. More amu will cause __________ ...
... 4. The atomic _______________ will give you this value for each element (number below the symbol) 5. For example, the atomic mass of Copper is 63.55 amu. This means that 1 mole of Copper will weigh 63.55 grams. 6. Don’t forget that mass is related to the number of amu. More amu will cause __________ ...
Chapter 9
... • How many moles of LiOH are required to react with 20 mol of CO2, the average amount exhaled by a person each day? ...
... • How many moles of LiOH are required to react with 20 mol of CO2, the average amount exhaled by a person each day? ...
The Mole - Piscataway High School
... What is Dimensional Analysis? A tool for solving conversion problems ...
... What is Dimensional Analysis? A tool for solving conversion problems ...
Chapter 9 Stoichiometry
... Actual yield is always less than the theoretical yield. LR is not always 100% used up. Can be due to human errors, not reacting to ...
... Actual yield is always less than the theoretical yield. LR is not always 100% used up. Can be due to human errors, not reacting to ...
CHEM 1411 EXAM I (Chapters 1, 2, 3): 25
... Thus, 223.7 + 0.27 = 223.97 from calculator, which must be corrected with the least decimal points of the components, and thus it is 224.0. So the question turns to 224.0 ÷ 4.21 = 53.20665083 from calculator, which must be corrected with the lease digit of the significant figures of the components ...
... Thus, 223.7 + 0.27 = 223.97 from calculator, which must be corrected with the least decimal points of the components, and thus it is 224.0. So the question turns to 224.0 ÷ 4.21 = 53.20665083 from calculator, which must be corrected with the lease digit of the significant figures of the components ...
Chapter 3 Notes
... Solving for molecular formulas: A molecular formula is a whole number MULTIPLE of an empirical formula. Ex The empirical formula of glucose is CH2O Multiply all subscripts x 6 = molecular formula C6H12O6 To solve these problems you need Empirical formula (often have to calculate this) Empirical for ...
... Solving for molecular formulas: A molecular formula is a whole number MULTIPLE of an empirical formula. Ex The empirical formula of glucose is CH2O Multiply all subscripts x 6 = molecular formula C6H12O6 To solve these problems you need Empirical formula (often have to calculate this) Empirical for ...
Stoichiometry
... • It is impossible to weigh a single atom, but one can easily establish the weight of an atom relative to another • We must establish a standard: – An atom of carbon-12 (six protons, six neutrons, six electrons) has a mass of exactly 12 atomic mass units (u) – Therefore, 1 atomic mass unit (u) is eq ...
... • It is impossible to weigh a single atom, but one can easily establish the weight of an atom relative to another • We must establish a standard: – An atom of carbon-12 (six protons, six neutrons, six electrons) has a mass of exactly 12 atomic mass units (u) – Therefore, 1 atomic mass unit (u) is eq ...
Calculations - The Student Room
... DEFINITION: The mole is the amount of substance in grams that has the same number of particles as there are atoms in 12 grams of carbon-12. DEFINITION: Relative atomic mass is the average mass of an atom compared to one twelfth of the mass of one atom of carbon-12 DEFINITION: Relative molecular mass ...
... DEFINITION: The mole is the amount of substance in grams that has the same number of particles as there are atoms in 12 grams of carbon-12. DEFINITION: Relative atomic mass is the average mass of an atom compared to one twelfth of the mass of one atom of carbon-12 DEFINITION: Relative molecular mass ...
Matter and Measurement
... on a particular set of metric units called SI units, which are based on the meter, the kilogram, and the second as the basic units of length, mass, and time, respectively. The metric system employs a set of prefixes to indicate decimal fractions or multiples of the base units. The SI temperature sca ...
... on a particular set of metric units called SI units, which are based on the meter, the kilogram, and the second as the basic units of length, mass, and time, respectively. The metric system employs a set of prefixes to indicate decimal fractions or multiples of the base units. The SI temperature sca ...