Download DEHRADUN INSTITUTE OF TECHNOLOGY Assignment:-3 DEPARTMENT OF ELECTRICAL ENGINEERING

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Transcript
DEHRADUN INSTITUTE OF TECHNOLOGY
DEPARTMENT OF ELECTRICAL ENGINEERING
INTRODUCTION TO ELECTRICAL ENGINEERING
Assignment:-3
(EA1210: Transformer)
1. Prove that in case of a single phase transformer emf per turn is constant. Also draw the phasor
diagram at leading, lagging and unity power factor.
2. Develop the equivalent circuit of transformer referred to (i) primary side (ii) secondary side.
3. Explain why the rating of a transformer is specified in terms of kVA and why do we prefer to
conduct Open Circuit Test on LV side and Short Circuit Test on HV side?. What is voltage
regulation?
4. A 50 kVA, 4400/220 V transformer has R1 = 3.45 Ω, R2 = 0.009 Ω. The values of reactances are X1
= 5.2 Ω and X2 = 0.015 Ω. Calculate for the transformer equivalent resistance and reactance (i)
referred to the primary side (ii) referred to the secondary side.(iii) also calculate total copper losses
first using individual resistances of the two windings and then using equivalent resistances as
referred to each side. (Ans.:- (i) 7.05 Ω, 11.2 Ω (ii) 0.0176 Ω, 0.028 Ω, (iii) 910.4 W
5. Following results were obtained on a 100 kVA, 11000/220 V single phase transformer:
(i)
O.C. Test (LV side)
220 V, 45 A, 2000 W
(ii)
S.C. Test (HV side)
500 V, 9.09 A, 3000 W
Determine equivalent circuit parameters of the transformer referred to low voltage side.
(Ans.:- RLV = 0.0145 Ω, XLV = 0.0165 Ω, ZLV = 0.175 + j0.45 = 0.483 & 68.800)
6.
The following results were obtained on a 50 KVA, 2400/120 V single phase transformer
Short circuit test (HV side)
:
810 W, 20.83 A, 92 V
Open circuit test (LV side)
:
396W, 9.365 A, 120 V
Calculate (i) the equivalent circuit parameters, (ii) efficiency at full load, 0.8 power factor
lagging. (ii) Efficiency at half of the full load, 0.82 power factor lagging. (Ans.:- Ro=24.2,
Xo=4.992, Z02=55, R02=36.3, X02=41.31, 97.07%)
7. A 100 kVA transformer has 400 turns on the primary and 80 turns on the secondary. The primary
and secondary resistances are 0.3 Ω and 0.1 Ω respectively and the corresponding reactances are 1.1
Ω and 0.035 Ω respectively. The supply voltage is 2200 V. Calculate the voltage regulation and
secondary terminal voltage for full – load having a p.f. of (i) 0.8 lagging (ii) 0.8 leading. (Ans.:- (i)
3.36%, 425.2V (ii) -1.54%, 446.8V)
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By: Nafees Ahamad
1