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Transcript
3.4 Justifying Constructions 1) Copying An Angle (http://www.mathopenref.com/constcopyangle.html) Proof This construction works by creating two congruent triangles. The angle to be copied has the same measure in both triangles The image below is the final drawing above with the red items added. Argument Reason 1 Line segments AK, PM are congruent Both drawn with the same compass width. 2 Line segments AJ, PL are congruent Both drawn with the same compass width. 3 Line segments JK, LM are congruent Both drawn with the same compass width. 4 Triangles ∆AJK and ∆PLM are congruent Three sides congruent (SSS). 5 Angles BAC, RPQ are congruent. CPCTC. Corresponding parts of congruent triangles are congruent - Q.E.D 2) Bisecting An Angle (http://www.mathopenref.com/constbisectangle.html Proof This construction works by effectively building two congruent triangles. The image below is the final drawing above with the red lines added and points A,B,C labelled. Argument Reason 1 QA is congruent to QB They were both drawn with the same compass width 2 AC is congruent to BC They were both drawn with the same compass width 3 ∆QAC and ∆QBC are congruent Three sides congruent (sss). QC is common to both. 4 Angles AQC, BQC are congruent CPCTC. Corresponding parts of congruent triangles are congruent 5 The line QC bisects the angle PQR Angles AQC, BQC are adjacent and congruent - Q.E.D 3) Constructing a 45 degree Angle (http://www.mathopenref.com/constangle45.html) Proof This construction works by creating an isosceles right triangle, which is a 45-45-90 triangle. The image below is the final drawing above with the red items added. Argument Reason 1 Line segment AB is perpendicular to PQ. Constructed that way. See Constructing the perpendicular bisector of a line. 2 Triangle APC is a right triangle Angle ACP is 90° (from step 1) 3 Line segments CP,CA are congruent Drawn with same compass width 4 Triangle ∆APC is isosceles. CP = AC 5 Angle APC has a measure of 45°. In isosceles triangle APC, base angles CPA and CAP are congruent. (See Isosceles Triangles). The third angle ACP is 90° and the interior angles of a triangle always add to 180. So both base angles CPA and CAP are 45°. - Q.E.D Try it yourself Click here for a printable worksheet containing two 45° angle exercises. When you get to the page, use the browser print command to print as many as you wish. The printed output is not copyright. 4) Constructing a 60 degree angle (http://www.mathopenref.com/constangle60.html) Proof This construction works by creating an equilateral triangle. Recall that an equilateral triangle has all three interior angles 60°. The image below is the final drawing above with the red items added. Argument Reason 1 Line segments AB, PB, PA are congruent All drawn with the same compass width. 2 Triangle APB is an equilateral triangle Equilateral triangles are those with all three sides the same length. 3 Angle APB has a measure of 60° All three interior angles of an equilateral triangle have a measure of 60°. See Equilateral triangle definition - Q.E.D Try it yourself Click here for a printable worksheet containing two 60° angle exercises. When you get to the page, use the browser print command to print as many as you wish. The printed output is not copyright. 5) Constructing a 30 degree angle Proof The image below is the final drawing above with the red items added. Argument Reason 1 Line segments PT, TR, RS, PS, TS are congruent (5 red lines) All created with the same compass width. 2 ∆PTR is an equilateral triangle, therefore angle mTPS 60 All three interior angles of an equilateral triangle have a measure of 60°. See Equilateral triangle definition 3 PR = PR Reflexive Property 4 ∆PTR ∆PSR SSS Property 5 TPR SPR CPCTC 6 mTPR mSPR mTPS Angle Addition Postulate 7 2mSPR 60 Substitution 8 mSPR 30 Division Property of Equality - Q.E.D Try it yourself Click here for a printable worksheet containing two 30° angle exercises. When you get to the page, use the browser print command to print as many as you wish. The printed output is not copyright. Constructing a Hexagon After doing this We start with a line segment AF. This will become one side of the hexagon. Because we are constructing a regular hexagon, the other five sides will have this length also. 1. Set the compass point on A, and set its width to F. The compass must remain at this width for the remainder of the construction. 2. From points A and F, draw two arcs so that they intersect. Mark this as point O. This is the center of the hexagon's circumcircle. Your work should look like this Constructing a Hexagon After doing this 3. Move the compass to O and draw a circle. This is the hexagon's circumcircle the circle that passes through all six vertices 4. Move the compass on to A and draw an arc across the circle. This is the next vertex of the hexagon. 5. Move the compass to this arc and draw an arc across the circle to create the next vertex. Your work should look like this Constructing a Hexagon After doing this 6. Continue in this way until you have all six vertices. (Four new ones plus the points A and F you started with.) 7. Draw a line between each successive pairs of vertices. Your work should look like this Constructing a Hexagon After doing this Your work should look like this 8. Done. These lines form a regular hexagon where each side is equal in length to AF. Extra Credit Worksheet: http://www.mathopenref.com/wshexagon.html EXTRA CREDIT WORKSHEET 1) (a) (b) (c) Construct a 45° angle on each end of the line below as in the example. What is the precise name of the triangle that results? What properties does this triangle have? (list 3). NAME:____________________ Example 2) Perform the 60° angle construction twice to create a 120° angle from two 60° angles that are adjacent (share a side) as in the example: 3) Draw a triangle where two interior angles are both 30° as in the example below. What is the name of triangles like this? 4) (a)5)Construct two hexagons that share the side below. It should look like the figure on the right. (b) Try to do it using only four circles and four arcs. 3.5 Inequalities in a Triangle Shortest Distance to a Line Corollary The shortest distance from a point to a line is measured along the perpendicular segment from the point to the line. (Lesson 3.3) Shortest Distance to a Plane Corollary The shortest distance from a point to a plane is the shortest line segment that can be drawn from the point to the plane. Side-Angle Inequality Theorem In a triangle, if one side is longer than another side, then the angle opposite the longer side is larger than the angle opposite the shorter side. Also the converse is true. a B C b A c If c b a, then mC mB mA If mC mB mA, then c b a, http://www.mathopenref.com/trianglesideangle.html IMPORTANT PROPERTY TO REMEMBER! Addition Property of Inequality If a > b and c > d, then a + c > b + d Triangle Inequality Theorem The Triangle Inequality Theorem states that the any side of a triangle must be less than the sum of the other 2 sides, and greater than the absolute value of their difference. |A - B| < C < A + B |B – C| < A < B + C |A - C| < B < A + C http://www.mathsisfun.com/definitions/triangle-inequality-theorem.html In other words, as soon as you know that the sum of 2 sides is less than (or equal to ) the measure of a third side, then you know that the sides do not make up a triangle . You only need to see if the two smaller sides are greater than the largest side! The interactive demonstration shows that the sum of the lengths of any 2 sides of a triangle must exceed the length of the third side. The demonstration also illustrates what happens when the sum of 1 pair of sides equals the length of the third side--you end up with a straight line! You can't make a triangle! Also, the third side must be larger than the absolute value of the difference of the other two sides. Extra Credit Worksheets: http://www.kutasoftware.com/FreeWorksheets/GeoWorksheets/5-The%20Triangle%20Inequality%20Theorem.pdf http://www.kutasoftware.com/FreeWorksheets/GeoWorksheets/5-Inequalities%20in%20One%20Triangle.pdf