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√
√
1
− x (1)
(x + 8) √
(x + 8) − (2x)
2 x
= √
⇒ y′ =
2
(x + 8)
2 x (x + 8)2
x
x+8
8−x
= √
.
2 x (x
+ 8)2
1
, and an equation of the tangent line is
At 4, 16 , y ′ = 144
1
1
1
5
y − 6 = 144 (x − 4), or y = 144
x + 36
. The slope of the normal line is −144,
so an equation of the normal line is y − 16 = −144(x − 4)
⇔ y = −144x + 3457
.
6
y=
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