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Transcript
Math 241, Quiz 8. 10/22/12.
Name:
• Read problems carefully. Show all work. No notes, calculator, or text.
• There are 15 points total.
§14.8, #33 (15 points): Use Lagrange Multipliers to find the maximum volume of a rectangular
box that is inscribed in a sphere of radius r.
Solution: The problem is to maximize V = (2x)(2y)(2z) = 8xyz subject to the constraint
g = x2 + y 2 + z 2 = r2 . We compute
∇V = h8yz, 8xz, 8xyi, ∇g = h2x, 2y, 2zi.
With λ 6= 0 and x, y, z > 0 (as spatial dimensions), we solve the system
4yz = λx, 4xz = λy, 4xy = λz, x2 + y 2 + z 2 = r2 .
Since x, y, z 6= 0, we solve for λ in the first three equations to obtain
4xz
4xy
4yz
=
=
= λ.
x
y
z
We take equations (1) and (2) together to get 4y 2 z = 4x2 z. Since z 6= 0, we find that y 2 = x2 .
Similarly, using equations (1) and (3) gives x2 = z 2 ; we conclude that x2 = y 2 = z 2 . We substitute
2
2
in the fourth equation
in the original system to get 3x
√
√ =3 r . Taking
√ the positive square root gives
3
x = y = z = r/ 3; hence, the volume is V = 8(r/ 3) = 8r /3 3.