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Using the TI-83 for Descriptive Statiistics The TI has 6 lists in which you can place data. When you input data you could do Stat…Edit…Enter and then input your data over any old data already there. Or, you could Stat…#4 for ClrList..2nd L1… , ..2nd L2 etc… Enter and then Stat…Edit…and begin to enter the data in the appropriate list. Enter the following data into L1. Be sure to hit Enter after your last piece of data. Then 2nd Quit. 23 15 34 67 68 78 93 85 34 12 42 93 34 67 67 67 23 32 15 78 To see the descriptive statistics calculated from your sample data: Stat…Calc…1-var Stat…Enter The calculator now needs to know where the data is. So punch 2 nd L1 then Enter. The default is L1 if you do not input a list. x is the mean x is the sum of all the data 2 x is the sum of the squares of the data items sx is the standard deviation if the data represents a sample x is the standard deviation if the data represents a population n is the number of data items min x is the minimum value in the data Q1 is the first quartile med is the median value Q 3 is the third quartile max x is the maximum value in the data To find the mode, order your data …Stat…#2 for Sort A.. 2nd L1.. Enter. Then go back and view the data and find the data item which appears the most. (Stat..Edit..) Let's try something a little different . Here is a frequency distribution instead of a list of data. x freq 3 6 11 3 14 4 21 9 23 8 Place the values for x in L1 and the corresponding frequencies in L2. To compute the descriptive statistics Stat…Calc… #1 for 1-var stat…2nd L1… , .... 2nd L2. The mean is 16 and the standard deviation 7.706 If you have grouped data, then in L1 you place the midpoints of the intervals. X Freq 0-9 3 10-19 6 20-29 8 30-39 2 The midpoint of the interval 0-9 is (0+9)\2 or 4.5; for 10-19, 14.5, etc. Place the midpoints in L1 and the corresponding frequencies in L2 and then proceed as in the previous example. The mean is 19.24 and the standard deviation of the sample is 9.05.